Velocity of the centre of mass is given by:
vcm=m1+m2m1v1+m2v2
Since m1=m2=m, we get:
vcm=2mm(4i^)+m(4j^)=2i^+2j^ m/s
Acceleration of the centre of mass is given by:
acm=m1+m2m1a1+m2a2
acm=2mm(6i^+6j^)+0=3i^+3j^ m/s2
Here, vcm=2(i^+j^) and acm=3(i^+j^).
Since the initial velocity and acceleration of the centre of mass are parallel to each other, the centre of mass moves in a straight line path.
Answer: straight line