The normal force N provides the necessary centripetal force for the mass to move in a circle:
N=mω2R
For the mass to remain stuck to the wall without falling, the upward frictional force must balance the downward gravitational force:
f≥mg
Since the maximum static friction is fmax=μN, we have:
μN≥mg
μ(mω2R)≥mg
μ≥ω2Rg
Substituting the given values g=10 m/s2, ω=5 rad/s, and R=4 m:
μ≥52×410
μ≥10010
μ≥0.1
The minimum coefficient of friction is 0.1.
Answer: 0.1