For parallel combination: keq=k1+k2=10+20=30 N/m
For sum, absolute errors add:
Δkeq=Δk1+Δk2=0.2+0.3=0.5 N/m
Percentage error =keqΔkeq×100=300.5×100=1.67%
In an experiment the values of two spring constants were measured as k_1=(10 ± 0.2) N / m and k_2=(20 ± 0.3) N / m. If these springs are connected in…
JEE Main 2026 — Physics Mechanics
In an experiment the values of two spring constants were measured as k1=(10±0.2)N/m and k2=(20±0.3)N/m. If these springs are connected in parallel, then the percentage error in equivalent spring constant is :
Held on 21 Jan 2026 · Verified 1 Jul 2026.
Options
- A
1.33%
- B
1.67%
- C
2.67%
- D
2.33%
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