Let T be the tension in the wire at a distance 3l from the top.
The length of the wire below this point is l−3l=32l.
The weight of this lower part of the wire is lw×32l=32w.
The total downward force (tension T) at this point is the sum of the weight W attached at the bottom and the weight of the lower part of the wire:
T=W+32w
The stress at this point is given by the tension divided by the cross-sectional area A:
Stress=AT=AW+32w=AW+32Aw
Comparing this with the given expression for stress, AW+γ2Aw, we get:
γ=3
Answer: 3