CM from mass m: xcm=3m2md=32d.
Distances: m is 2d/3 from CM, 2m is d/3 from CM.
Icm=m(2d/3)2+2m(d/3)2=94md2+92md2=32md2.
L=Iω⇒ω=IL=2md23L.
Two small balls with masses m and 2 m are attached to both ends of a rigid rod of length d and negligible mass. If angular momentum of this system is L about an axis (A) passing through its centre of mass and perpendicular to the rod then angular velocity of the system about A is :
Held on 23 Jan 2026 · Verified 6 Jul 2026.
5md22L
34md2L
23md2L
md22L
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