Using v² = u² - 2gh, at max height v = 0. So h = u²/(2g) = 900/20 = 45 m
Back to JEE Main 2026 Mechanics
JEE Main 2026 — Physics Mechanics
easy
mcq
2026
Official previous-year question
Verified 30 May 2026.
Question
A particle of mass 2 kg is projected vertically upward with a speed of 30 m/s. The maximum height reached by the particle is (g = 10 m/s²):
Options
- A
25 m
- B
45 m
- C
60 m
- D
90 m
Solution
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