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Net gravitational force at the center of a square is found to be F_1 when four particles having mass M, 2 M, 3 M and 4 M are placed at the four…

JEE Main 2026 — Physics Mechanics

2026mcqmedium

Net gravitational force at the center of a square is found to be F1F_{1}F1​ when four particles having mass M,2M,3MM, 2 M, 3 MM,2M,3M and 4M4 M4M are placed at the four corners of the square as shown in figure and it is F2F_{2}F2​ when the positions of 3M3 M3M and 4M4 M4M are interchanged. The ratio F1F2\frac{F_{1}}{F_{2}}F2​F1​​ is α5\frac{\alpha}{\sqrt{5}}5​α​. The value of α\alphaα is ____\_\_\_\_____.

JEE Main 2026 Physics, Gravitation — question figure

Official previous-year question

Held on 22 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    252 \sqrt{5}25​

  2. B

    3

  3. C

    1

  4. D

    2

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