Let the acceleration of the system be a. The total mass on the right side is m2+m3=4+6=10 kg, and the mass on the left side is m1=4 kg. Since 10 kg >4 kg, the right side accelerates downwards and the left side accelerates upwards.
The common acceleration a of the system is given by:
a=m1+m2+m3(m2+m3)−m1g
a=4+4+610−4g=146g=73g
For mass m1, the equation of motion is:
T1−m1g=m1a
T1=m1(g+a)=4(g+73g)=4(710g)=740g
For mass m3, the equation of motion is:
m3g−T2=m3a
T2=m3(g−a)=6(g−73g)=6(74g)=724g
The ratio of the tensions is:
T2T1=724g740g=2440=35
Answer: 5/3