Let the acceleration of the system be a and the tension in the string be T.
The equations of motion for the two masses are:
6g−T=6a
T−2g=2a
Adding the two equations, we get:
4g=8a
⇒a=84g=2g
Substituting g=10 m/s2, the acceleration is:
a=210=5 m/s2
The 6 kg mass is released from rest (u=0) and travels a downward distance s=6 m.
Using the kinematic equation v2=u2+2as:
v2=0+2×5×6
v2=60
v=60≈7.74 m/s
Answer: 7.74
