Total energy of satellite in orbit: E=−2rGMm=−2rgRE2m
E1=−2(1.5RE)gRE2m=−3gREm
E2=−2(3RE)gRE2m=−6gREm
Energy supplied =E2−E1=−6gREm+3gREm=6gREm
=610×6×106×100=109 J =1000×106 J
α=1000
JEE Main 2026 — Physics Mechanics
Initially a satellite of 100 kg is in a circular orbit of radius 1.5RE. This satellite can be moved to a circular orbit of radius 3RE by supplying α×106 J of energy. The value of α is ____. (Take Radius of Earth RE=6×106 m and g=10 m/s2)
Held on 21 Jan 2026 · Verified 6 Jul 2026.
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