Given: 50 vernier divisions = 48 main divisions and 1 main division = 0.05 mm
50 vernier divisions = 48 × 0.05 = 2.4 mm
1 vernier division = 2.4/50 = 0.048 mm
Least count = 1 main division - 1 vernier division = 0.05 - 0.048 = 0.002 mm
JEE Main 2026 — Physics Mechanics
In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division =0.05 mm, then the least count of the vernier callipers is ____ mm.
Held on 24 Jan 2026 · Verified 6 Jul 2026.
0.005
0.05
0.002
0.02
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