At t=0, a body of mass 100 g starts moving under the influence of a force (5 i+10 j) N. After 2 s its position is (2x i+5y j) m. The ratio x:y is .
JEE Main 2026 — Physics Mechanics
2026mcqmedium
At t=0, a body of mass 100 g starts moving under the influence of a force (5i^+10j^) N. After 2 s its position is (2xi^+5yj^) m. The ratio x:y is ______.
Official previous-year question
Held on 4 Apr 2026 · Verified 6 Jul 2026.
Options
A
1:2
B
2:5
C
5:2
D
5:4
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Solution
Mass m=100 g=0.1 kg
Force F=5i^+10j^ N
Acceleration a=mF=0.15i^+10j^=50i^+100j^ m/s2
Since the body starts from rest, initial velocity u=0.
Position after t=2 s is given by r=ut+21at2
r=21(50i^+100j^)(2)2=100i^+200j^ m
Comparing with the given position r=2xi^+5yj^:
2x=100⇒x=50
5y=200⇒y=40
The ratio x:y=50:40=5:4
Answer: 5:4
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