At A: KEA=K, vA=v, angle =60°.
At B (highest point): vB=vcos60°=v/2, so KEB=K/4.
At C (same level as A): by energy conservation, KEC=K.
∣KEB−KEC∣=∣K/4−K∣=3K/4.
Ratio =K3K/4=43, i.e., 3:4.
An object is projected with kinetic energy K from a point A at an angle 60∘ with the horizontal. The ratio of the difference in kinetic energies at points B and C to that at point A (see figure), in the absence of air friction is :

Held on 23 Jan 2026 · Verified 6 Jul 2026.
1:4
2:3
3:4
1:2
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