Since the assembly moves with a constant velocity, the acceleration of the mass is zero. The mass is in equilibrium relative to the incline.
The frictional force f acting on the mass balances the component of gravity along the inclined plane. Therefore, the magnitude of the frictional force is:
f=mgsin30∘
Substituting the given values (m=1 kg, g=10 m/s2):
f=1×10×21=5 N
The direction of the frictional force is upwards along the incline. Since the incline makes an angle of 30∘ with the horizontal, the frictional force makes an angle of 90∘−30∘=60∘ with the vertical upward direction.
The displacement s of the assembly in time t=2 s is vertically upwards:
s=vt=4×2=8 m
The work done by the frictional force is:
W=fscos60∘
W=5×8×21=20 J
Answer: 20