For a floating cubical block in equilibrium, the buoyant force equals the weight:
ρe⋅g⋅A⋅hs=ρb⋅g⋅A⋅H
where hs is the submerged height.
Simplifying: hs=ρeρb⋅H=900600×8.0=32×8.0
=5.33 cm ≈ 5.3 cm
A cubical block of density ρb=600 kg/m3 floats in a liquid of density ρe=900kg/m3. If the height of block is H=8.0 cm then height of the submerged part is ____ cm.
Held on 24 Jan 2026 · Verified 6 Jul 2026.
6.3
4.3
5.3
7.3
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