Let the length of the inclined plane be s.
For the smooth inclined plane, the acceleration of the block is a1=gsinθ.
The time taken is t1=2t. Using the second equation of motion s=ut+21at2 with u=0:
s=21(gsinθ)(2t)2=81gsinθt2
For the rough inclined plane, the acceleration of the block is a2=g(sinθ−μcosθ).
The time taken is t2=t. Using the equation of motion again:
s=21g(sinθ−μcosθ)t2
Equating the two expressions for s:
81gsinθt2=21g(sinθ−μcosθ)t2
41sinθ=sinθ−μcosθ
Given θ=45∘, we have sin45∘=cos45∘=21. Substituting these values:
41=1−μ
μ=1−41=43=0.75
We are given μ=100α.
100α=0.75⇒α=75
Answer: 75