LBLA=31 and dBdA=2
ΔLA=AAYAFALA and ΔLB=ABYBFBLB
Given, FA=FB and YA=YB
ΔLBΔLA=ABYBFBLBAAYAFALA=(LBLA)(AAAB)
ΔLBΔLA=(LBLA)(4π dA24π dB2)=(LBLA)(dAdB)2
ΔLBΔLA=(31)(21)2=121
Two wires A and B are made of same material having ratio of lengths LBLA=31 and their diameters ratio dBdA=2. If both the wires are stretched using same force, what would be the ratio of their respective elongations?
Held on 7 Apr 2025 · Verified 6 Jul 2026.
1:6
1:12
3:4
1:3
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