
U1=(ρA×10)g×5+(ρA6)g×3Ui=ρAg(50+18)Ui=68ρAg
Uf=(ρA×16)g×4=(ρAg)×64
ω=ΔU=4×ρAg=4×1000×2×10=8×104 J
JEE Main 2025 — Physics Mechanics
Two cylindrical vessels of equal cross sectional area of 2 m2 contain water up to height 10 m and 6 m , respectively. If the vessels are connected at their bottom then the work done by the force of gravity is : (Density of water is 103 kg/m3 and g=10 m/s2)
Held on 3 Apr 2025 · Verified 6 Jul 2026.
1×105 J
4×104 J
6×104 J
8×104 J
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