A satellite of mass M 2 is revolving around earth in a circular orbit at a height of R 3 from earth surface. The angular momentum of the satellite is…
JEE Main 2025 — Physics Mechanics
2025integerhard
A satellite of mass 2M is revolving around earth in a circular orbit at a height of 3R from earth surface. The angular momentum of the satellite is MxGMR. The value of x is ______ , where M and R are the mass and radius of earth, respectively. ( G is the gravitational constant)
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Held on 23 Jan 2025 · Verified 6 Jul 2026.
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Solution
orbital velocity v0=4R/3GM=4R3GM Angular momentum of satellite =2Mv034R=2M⋅4R3GM⋅34R=M3GMRx=3 (ii) Since mass of satellite is comparable to the mass of earth.
(34R)2 G.M. 2M=2Mω2⋅98Rω=128R381GM Angular momentum of satellite about common centre of mass, $\begin{aligned} & L=\frac{M}{2} \cdot\left(\frac{8 R}{9}\right)^2 \cdot \omega \ & L=M \sqrt{\operatorname{GMR}\left(\frac{8}{81}\right)} \ & x=\frac{81}{8} \simeq 10 \end{aligned}$
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