v=dtdx=2tC0+2C(t−2)a=dtdv=2C0+2C
A particle moves along the x-axis and has its displacement x varying with time t according to the equation x=c0(t2−2)+c(t−2)2 where c0 and c are constants of appropriate dimensions. Then, which of the following statements is correct?
Held on 3 Apr 2025 · Verified 6 Jul 2026.
the acceleration of the particle is 2c0
the acceleration of the particle is 2 c
the initial velocity of the particle is 4 c
the acceleration of the particle is 2(c+c0)
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