$\begin{aligned}
& \theta=5 \mathrm{t}^2-8 \mathrm{t} \
& \omega=\frac{\mathrm{d} \theta}{\mathrm{dt}}=10 \mathrm{t}-8 \
& \alpha=\frac{\mathrm{d} \omega}{\mathrm{dt}}=10 \
& \therefore \mathrm{p}=\tau \omega \
& =(\mathrm{I} \alpha) \omega \
& =\left(\frac{\mathrm{mR}^2}{2}\right) \alpha \omega \
& =\left(\frac{\mathrm{mR}^2}{2}\right)(10)(10
\end{aligned}Put\mathrm{t}=2\mathrm{p}=60 \mathrm{mR}^2$