
So, N=mgcosθ+rmv02sinθ fr=μmgcosθ+rμmv02sinθ $\begin{aligned}
& \text { And } \frac{m v_0^2}{r} \cos \theta=m g \sin \theta+f_r \
& \Rightarrow \frac{m v_0^2}{r} \cos \theta-m g \sin \theta=\mu\left(m g \cos \theta+\frac{m v_0^2}{r} \sin \theta\right) \
& \Rightarrow\left(v_0^2-g r \tan \theta\right)=\mu\left(v_0^2 \tan \theta+g r\right) \
& \Rightarrow \mu=\frac{v_0^2-g r \tan \theta}{g r+v_0^2 \tan \theta}
\end{aligned}$