⟨p⟩=4(2i^+3j^)⋅(3i^+6j^)=6a=(mF=21i^+43j^)v at t=4sec=(21i^+43j^)×4=(2i^+3j^)Pins =(2i^+3)(2i^+3j^)=13Pins ⟨P⟩=136
A body of mass 4 kg is placed on a plane at a point P having coordinate (3,4) m. Under the action of force overrightarrow F=(2 i+3 j) N, it moves to…
JEE Main 2025 — Physics Mechanics
A body of mass 4 kg is placed on a plane at a point P having coordinate (3,4)m. Under the action of force F=(2i^+3j^)N, it moves to a new point Q having coordinates (6,10)m in 4 sec . The average power and instanteous power at the end of 4 sec are in the ratio of :
Held on 28 Jan 2025 · Verified 6 Jul 2026.
Options
- A
13:6
- B
4:3
- C
1:2
- D
6:13
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