
21 m×100+0=21mVB2+mg(R−2R3)100=VB2+2gR(1−23]VB2=100−20(2−3)VB2=60+203)K.EB=21mVB2=2m(60+203)21 m(100)=21mV2100=mg(23R)100 VC2=60 VC2=40 K.EC=21mVVC2=21 m(40)K.EB=4060+203=23+23=23+3
JEE Main 2025 — Physics Mechanics
A body of mass 100 g is moving in circular path of radius 2 m on vertical plane as shown in figure. The velocity of the body at point A is 10 m/s. The ratio of its kinetic energies at point B and C is : 
(Take acceleration due to gravity as 10 m/s2 )
Held on 22 Jan 2025 · Verified 6 Jul 2026.
32+2
32+3
23+3
23−2
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