The velocity of the ant can be found as follows:
v===dtdSdtd(2t2j^+5k^)4tj^...(1)
At t=1s, from equation (1), it follows that
v=4j^
Position of an ant ( S in metres) moving in Y−Z plane is given by S=2t2j^+5k^ (where t is in second). The magnitude and direction of velocity of the ant at t=1s will be :
Held on 27 Jan 2024 · Verified 6 Jul 2026.
16ms−1 in y-direction
4ms−1 in x-direction
9ms−1 in z-direction
4ms−1 in y-direction
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