Given: RP=3RE,MP=6ME
Escape velocity is given by, v=R2GM
Therefore,
vE=RE2GME...(i)
vP=RP2GMP...(ii)
⇒vPvE=2
⇒vP=2vE=211.2=7.9kms−1
JEE Main 2024 — Physics Mechanics
Escape velocity of a body from earth is 11.2kms−1. If the radius of a planet be one-third the radius of earth and mass be one-sixth that of earth, the escape velocity from the plate is:
Held on 30 Jan 2024 · Verified 6 Jul 2026.
11.2kms−1
8.4kms−1
4.2kms−1
7.9kms−1
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