From the dimensional checking of the equation, we can say the dimensions of [B]=[x2]=[L2]
And dimensions of [A]=[tE][x2]=[T][ML2T−2][L2]=[MT−1]1
Hence, [A]=[M−1T]
Required value, [AB]=[L2M−1T1]
Consider two physical quantities A and B related to each other as E=AtB−x2 where E,x and t have dimensions of energy, length and time respectively. The dimension of AB is
Held on 31 Jan 2024 · Verified 6 Jul 2026.
L−2M1T0
L2M−1T1
L−2M−1T1
L0M−1T1
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