
Impulse J=0.2Ns
⇒J=∫Fdt=0.2Ns
Now, angular impulse (M) will be
Mc=∫τdt
=∫F2Ldt
=2L∫Fdt=2L×J
=20.3×0.2
=0.03
Moment of inertia of the rod about the centre of mass, Icm=12ML2=122×(0.3)2=60.09
Angular impulse will be equal to the change in angular momentum.
M=Icm(ωf−ωi)
⇒0.03=60.09(ωf)
⇒ωf=2rads−1
For angular displacement, we can write θ=ωt
⇒t=ωθ=2×2π=4πs.
Therefore, x=4.