amp; Total energy =2(2R)−GMmamp; if energy =6104R is added then amp;4R−GMm+6104R=2r−GMmamp; where r is new radius of revolving and g=R2GMamp;−4mgR+6104R=−2rmgR2(m=103 kg)amp;−4103×10×R+6104R=−2r103×10×R2amp;−41+61=−2rRamp;r=6R
A satellite of 103 kg mass is revolving in circular orbit of radius 2R. If 6104RJ energy is supplied to the satellite, it would revolve in a new circular orbit of radius (use g=10 m/s2,R= radius of earth)
Held on 9 Apr 2024 · Verified 6 Jul 2026.
2.5R
3R
4R
6R
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