Time period of circular motion is given by,
v2πR=T⇒v=T2πR
Now, maximum height H=2gv2sin2θ
⇒4R=T24π2R22gsin2θ
⇒sinθ=π2R2gT2
⇒θ=sin−1(π2R2gT2)21
A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle θ to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection θ is then given by :
Held on 1 Feb 2024 · Verified 6 Jul 2026.
sin−1[π2R2gT2]21
sin−1[2gT2π2R]21
cos−1[π2R2gT2]21
cos−1[2gT2πR]21
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