P=cos(kt)i^−sin(kt)j^;∣P∣=1∵P=mv∴P^=v^⇒v^=cos(kt)i^−sin(kt)j^a^=k−ksin(kt)i^−kcos(kt)j^⇒a^=−sinkti^−cosktj^∵F^=a^=−sinkti^−cosktj^cosθ=∣F^∣∣P^∣F^⋅P^=−1×1sinktcost+sinktcost=0⇒θ=2π
A particle moves in x−y plane under the influence of a force F such that its linear momentum is p(t)=i^cos(kt)−j^sin(kt). If k is constant, the angle between F and p will be :
Held on 5 Apr 2024 · Verified 1 Jul 2026.
4π
6π
2π
3π
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