Let the gravitational force of attraction be F=R3/2GMm.
Now, this gravitational force will provide the required centripetal force. Therefore,
R3/2GMm=mω2R
⇒ω2∝R5/21∵T=ω2π
⇒T2∝R5/2
A light planet is revolving around a massive star in a circular orbit of radius R with a period of revolution T. If the force of attraction between planet and star is proportional to R−3/2 then choose the correct option :
Held on 1 Feb 2024 · Verified 6 Jul 2026.
T2∝R5/2
T2∝R7/2
T2∝R3/2
T2∝R3
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