Given: F=ax2+bt21
Dimension of [a]=[x2][F]=[L2][MLT−2]=[M1L−1T−2]
Dimension of [b]=[t21][F]=[T21][MLT−2]=[M1L1T−25]
Required value, [ab2]=[M1L−1T−2][M2L2T−5]=[M1L3T−3]
A force is represented by F=ax2+bt21, where x= distance and t= time. The dimensions of ab2 are :
Held on 31 Jan 2024 · Verified 6 Jul 2026.
[ML3T–3]
[MLT–2]
[ML–1T–1]
[ML2T–3]
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