m=800 kgr=300 mθ=30∘μs=0.2 Vmax=Rg[1−μtanθtanθ+μ]=300×g×[1−0.2×tan30∘tan30∘+0.2]=300×10×[1−0.2×0.570.57+0.2]Vmax=51.4 m/s
A car of 800 kg is taking turn on a banked road of radius 300 m and angle of banking 30∘. If coefficient of static friction is 0.2 then the maximum speed with which car can negotiate the turn safely: (g=10 m/s2,3=1.73)
Held on 6 Apr 2024 · Verified 6 Jul 2026.
264 m/s
51.4 m/s
70.4 m/s
102.8 m/s
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