Elongation in uniform wire under load is given by, Δl=SYFl, where S is area of cross-section.
As F is same for both wire and Δl is also same, we can write
FΔl=SYl⇒SAYAlA=SBYBlB
⇒(2.5×10−5)×YA5=(3×10−5)×YB6
⇒YBYA=1
Under the same load, wire A having length 5.0m and cross section 2.5×10−5m2 stretches uniformly by the same amount as another wire B of length 6.0m and a cross section of 3.0×10−5m2 stretches. The ratio of the Young's modulus of wire A to that of wire B will be:
Held on 31 Jan 2023 · Verified 6 Jul 2026.
1:4
1:1
1:10
1:2
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