Mass of the disc in terms of density can be written as, m=ρ(πR2t).
⇒R2=ρπtm
Now moment of inertia of the disc about the diameter is, 4mR2.
Therefore,
I=4mR2=4ρπtm2⇒I∝ρt1
Required ratio, I2I1=ρ1t1ρ2t2=35×10.5=65
Hence, x=5.
JEE Main 2023 — Physics Mechanics
Two discs of same mass and different radii are made of different materials such that their thicknesses are 1cm and 0.5cm respectively. The densities of materials are in the ratio 3:5. The moment of inertia of these discs respectively about their diameters will be in the ratio of 6x. The value of x is ______.
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