The moment of inertia of a semicircular ring about a line perpendicular to the plane of the ring and passing through its centre is given asI=MR2, where m andR are the mass and radius of the ring. Comparing the given value
.I=MR2=x1MR2
⇒x=1
The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, isx1MR2, where R is the radius and M is the mass of the semicircular ring. The value of x will be _______.
Held on 8 Apr 2023 · Verified 6 Jul 2026.
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