
We have, ICM=21MR2
Since AB is parallel to diameter and at a distance of 32R from it, using parallel axis theorem,
IAB=2mR2+m(32R)2=1817mR2
Thus, the ratio is
∴ICMIAB=21MR21817MR2=917
Thus, x=17
JEE Main 2023 — Physics Mechanics
ICM is moment of inertia of a circular disc about an axis (CM) passing through its center and perpendicular to the plane of disc. IAB is its moment of inertia about an axis AB perpendicular to plane and parallel to axis CM at a distance 32R from center, where R is the radius of the disc. The ratio of IAB and ICM is x:9. The value of x is ______.

Held on 25 Jan 2023 · Verified 6 Jul 2026.
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