Given, E=−r2K
Gravitational field and gravitational potential is related as E=−drdV
So, −drdV=r2−K
Integrating the above relation,
∫10VdV=∫23r2Kdr
⇒V−10=K[21−31]
⇒V−10=6K⇒V=66+10⇒V=11Jkg−1
If the gravitational field in the space is given as (−r2K). Taking the reference point to be at r=2cm with gravitational potential V=10Jkg−1. Find the gravitational potentials at r=3cm in SI unit (Given, that K=6Jcmkg−1)
Held on 30 Jan 2023 · Verified 6 Jul 2026.
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