Unit vector in the direction of P×Qisn^=∣P×Q∣P×Q.
Here, P×Q=∣i^34j^33k^22.5∣=32i^+2j^−3k^
And ∣P×Q∣=(23)2+(21)2+(3)2=4=2
⇒∣P×Q∣P×Q=21(32i^+2j^−3k^)
=41(3i^+j^−23k^)⇒x=4
JEE Main 2023 — Physics Mechanics
If P=3i^+3j^+2k^ and Q=4i^+3j^+2.5k^ then, the unit vector in the direction of P×Q is x1(3i^+j^−23k^). The value of x is
Held on 25 Jan 2023 · Verified 6 Jul 2026.
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