Considering rotational axis as the diametrical axis for sphere and axis of cylinder. Then
K12=52R2 and K22=21R2
∴K2K1=1/22/5=54
⇒K2K1=52
Comparing it with the given value in the question,
52=x2
∴ x=5
A solid sphere and a solid cylinder of same mass and radius are rolling on a horizontal surface without slipping. The ratio of their radius of gyrations respectively (ksph:kcyl) is 2:x. The value of x is _______.
Held on 15 Apr 2023 · Verified 6 Jul 2026.
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