Orbital velocity of a satellite in circular motion around a planet,
vo=RGM∝R1
Now, v2v1=R1R2=3200800=21
Hence, the value of x=2.
Two satellites S1 and S2 are revolving in circular orbits around a planet with radius RI=3200km and R2=800km respectively. The ratio of speed of satellite S1 to the speed of satellite S2 in their respective orbits would be x1 where x=
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Net gravitational force at the center of a square is found to be $F_{1}$ when four particles having mass $M, 2 M, 3 M$ and $4 M$ are placed at the four corners of the square as shown in figure and it is $F_{2}$ when the positions of $3 M$ and $4 M$ are interchanged. The ratio $\frac{F_{1}}{F_{2}}$ is $\frac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is $\_\_\_\_$. 
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Work through every JEE Main Mechanics PYQ, year by year.