Velocity of COM = (m₁v₁ + m₂v₂)/(m₁ + m₂) = (10 × 14 + 4 × 0)/(10 + 4) = 140/14 = 10 m/s
JEE Main 2022 — Physics Mechanics
Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of the lighter block. The velocity of the center of mass is:
Verified 30 May 2026.
30 m/s
20 m/s
10 m/s
5 m/s
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