Velocity of COM = (m₁v₁ + m₂v₂)/(m₁ + m₂) = (10 × 14 + 4 × 0)/(10 + 4) = 140/14 = 10 m/s
Back to JEE Main 2022 Mechanics
JEE Main 2022 — Physics Mechanics
easy
mcq
2022
Official previous-year question
Verified 30 May 2026.
Question
Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of the lighter block. The velocity of the center of mass is:
Options
- A30 m/s
- B20 m/s
- C10 m/s
- D5 m/s
Solution
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Mechanics in other years
More JEE Main Mechanics Questions
A particle of mass 2 kg is projected vertically upward with a speed of 30 m/s. The maximum height reached by the particle is (g = 10 m/s²):
2026
easy
mcq
The range of a projectile launched with initial velocity u at angle θ with horizontal is given by:
2025
medium
mcq
A ball is projected at 45° with speed 20 m/s. Find the maximum height reached (in metres). Take g = 10 m/s².
2024
easy
numerical_value
A particle moves in a circle of radius R with constant angular velocity ω. If the centripetal acceleration is 4 m/s² when R = 2 m, what is the angular velocity?
2024
easy
mcq
A particle moves in a circle of radius R with constant speed v. Its centripetal acceleration is
2024
easy
mcq