Angular momentum of a particle is given by,
L=r×P=r×mv also m=1kg.
⇒L=(3i^−j^)×(3j^+k^)=(9k^−3j^−i^)Nms
The magnitude of the angular momentum will be,
⇒∣L∣=92+32+12=91Nms
Therefore, the value of x=91.
The position vector of 1kg object is r=(3i^−j^)m and its velocity v=(3j^+k^)ms−1. The magnitude of its angular momentum is xNms, where x is
Held on 28 Jun 2022 · Verified 6 Jul 2026.
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