Here, gain in kinetic energy=loss in potential energy
Now loss in potential energy of particle in falling from height y to y0 is mg(y−y0).
So, ΔKE=K−0=−[mg(y−y0)−mgy]
Thus, kinetic energy at point B is K=mgy0
In the given figure, the block of mass m is dropped from the point ′A′. The expression for kinetic energy of block when it reaches point ′B′ is

Held on 29 Jun 2022 · Verified 6 Jul 2026.
mgy0
21mgy02
21mgy2
mg(y−y0)
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