Given: z=a2x3y21
Relative error is given by
zΔz=[3×xΔx+21×yΔy]
Now, maximum percentage error in z is
zΔz×100=[3(4)+21(2)]×100
=18.
For z=a2x3y21, where 'a' is a constant. If percentage error in measurement of 'x' and 'y' are 4and 12, respectively, then the percentage error for 'z' will be _____.
Held on 25 Jun 2022 · Verified 6 Jul 2026.
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