The position vector of the particle can be written as,
r=3ti^+5t3j^+7k^
The velocity of the particle will be,
v=dtdr=3i^+15t2j^
Now the acceleration of the particle will be,
a=dtdv=dt2d2r=30tj^
At t=1s⇒dt2d2r=30j^
At time t=0 a particle starts travelling from a height 7z^cm in a plane keeping z coordinate constant. At any instant of time, it's position along the x and y directions are defined as 3t and 5t3 respectively. At t=1s acceleration of the particle will be
Held on 28 Jul 2022 · Verified 6 Jul 2026.
−30y
30y
3x+15y
3x+15y+7z^
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