Let the maximum elongation of the spring be x.

Using energy conservation
Loss in kinetic energy of both blocks=Gain in spring energy
21mv2×2=21kx2
⇒(0.25)v2=21×2×x2
⇒41v2=21×2×x2
∴x=2v
As per the given figure, two blocks each of mass 250g are connected to a spring of spring constant 2Nm−1. If both are given velocity v in opposite directions, then maximum elongation of the spring is

Held on 26 Jul 2022 · Verified 6 Jul 2026.
22v
2v
4v
2v
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