Given that energy density U=βαsinktαx
As ktαx should be dimensionless, the dimensions of αx and kt should be same.
⇒[α][x]=[k][t]⇒[α]=[x][k][t]
Now,
[U]=[β][α]
⇒[β]=[U][α]=[x][VE][k][t]=[x][VE][tE][t]
⇒[β]=[L][L3]=[M0L2T0]
JEE Main 2022 — Physics Mechanics
An expression of energy density is given by u=βαsin(ktαx), where α,β are constants, x is displacement, k is Boltzmann constant and t is the temperature. The dimensions of β will be
Held on 27 Jul 2022 · Verified 6 Jul 2026.
[ML2T−2θ−1]
[M0L2T−2]
[M0L0T0]
[M0L2T0]
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