Maximum acceleration of the upper block will be,
amax=μg=0.5×9.8=4.9ms−2
Therefore, maximum force that can be applied on the lower block is,
Fmax=(2+8)×4.9=49N
A system of two blocks of masses m=2kg and M=8kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is 0.5. The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be (g=9.8ms−2)

Held on 27 Jun 2022 · Verified 6 Jul 2026.
9.8N
39.2N
49N
78.4N
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